Nice I mean I kinda said the answer in his question Conversion of PbSO4 to PbS ... chemistry. Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Since the ion has a -2 charge, the oxidation state of sulfur must be +6. Therefore oxidation number of Pb is +2. Oxidation number of Pb is +2 Conversion of P b S O 4 to P b S is : A. reduction of S. B. oxidation of S. C. dissociation. It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers). PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. +1 +3 0-1 +2 +1. Therefore x+6-8=0. H in H2 : 0. D. none of these. Sum of all oxidation number =0. Oxidation number of S=+6. If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. Oxidation number pbso4 Therefore, the oxidation number of S in PbSO4 is +6. For a simple ion, like Pb in PbSO4, it is the same as the ionic charge, ie +2. The anodic oxidation of solid Pb in H 2 SO 4 to form PbSO 4 has been investigated by rotating disc, potentiostatic pulse and ac impedance measurements. How to calculate oxidation number of Pb in PbSO4?And Explain? Pb +2 S-2 + H +1 2 O-1 2 → Pb +2 S +6 O-2 4 + H +1 2 O-2 . Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). MEDIUM. Add your answer and earn points. b) Identify and write out all redox couples in reaction. H2O2 + PbS --> PbSO4 + H2O. Oxidation number of O=-2. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. Thank me later Shaawana is waiting for your help. Now, since O is always -2, the S must be +6 to make the whole compound zero. A compound doesn't have an oxidation number, but an element in a compound does. Which substance is the reducing agent in the following reaction? Pb. Expert Answer: Let the oxidation number of Pb=x. You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. Explanation: The oxidation number of S in P b S O 4 = 6. Pb in PbSO4 : +2. What is the oxidation number of phosphorous in the H3PO2 molecule? Pb +2 S -2 + H +1 2 O -1 2 → Pb +2 S +6 O … Within polyatomic ions, you can frequently have oxidation states that are not "normal". 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